hi all
who can explain the difference between bootstrap standard error and standard deviation ? in the outcome of bootstrap ,standard error have the same value with standard deviation. which one i should get into research outcome?
thanks in advance!
differrence between standard error and standar deviation
- cringle
- SmartPLS Developer
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- Joined: Tue Sep 20, 2005 9:13 am
- Real name and title: Prof. Dr. Christian M. Ringle
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Hi,
these bootstrapping results are equivalent (I quoted a good link, when this question was asked previously but cannot find it right away).
Best regards
Christian
these bootstrapping results are equivalent (I quoted a good link, when this question was asked previously but cannot find it right away).
Best regards
Christian
Prof. Dr. Christian M. Ringle, Hamburg University of Technology (TUHH), SmartPLS
- Literature on PLS-SEM: https://www.smartpls.com/documentation
- Google Scholar: https://scholar.google.de/citations?use ... AAAJ&hl=de
- Literature on PLS-SEM: https://www.smartpls.com/documentation
- Google Scholar: https://scholar.google.de/citations?use ... AAAJ&hl=de
Well,
try harder next time ;) ! viewtopic.php?t=151
These links may provide the information you are looking for:
http://www.uvm.edu/~dhowell/StatPages/R ... pping.html
http://www.stat.wisc.edu/~larget/math496/bootstrap.html
Best regards
Christian
try harder next time ;) ! viewtopic.php?t=151
These links may provide the information you are looking for:
http://www.uvm.edu/~dhowell/StatPages/R ... pping.html
http://www.stat.wisc.edu/~larget/math496/bootstrap.html
Best regards
Christian
Administration Team
Thanks, although this is not answering the question; refer to the comment which I have found under the link you quoted:
"Theory tells us that the standard error of the sample mean equals the population standard deviation divided by the square root of the sample size. In cases in which the population size is unknown, we may use the sample standard deviation instead of the population standard deviation."
So why is the calculation of the std error not taking the sample size into account (which should be the number of cases selected for bootstrap - as this represents the sample size)?
Could this be an error of the smartPLS SW?
"Theory tells us that the standard error of the sample mean equals the population standard deviation divided by the square root of the sample size. In cases in which the population size is unknown, we may use the sample standard deviation instead of the population standard deviation."
So why is the calculation of the std error not taking the sample size into account (which should be the number of cases selected for bootstrap - as this represents the sample size)?
Could this be an error of the smartPLS SW?
AP
- cringle
- SmartPLS Developer
- Posts: 818
- Joined: Tue Sep 20, 2005 9:13 am
- Real name and title: Prof. Dr. Christian M. Ringle
- Location: Hamburg (Germany)
- Contact:
In bootstrapping, the standard deviation of the distribution would be the standard error.
As you can see in the SmartPLS results tables, this kind computation was implemented into SmartPLS to get the t-value:
w / se
If you do not "like" this kind of "standard" computation for any reason, you can just take the bootstrap results for each subsample (just look into the results tables) and compute the t-value as you prefer
As you can see in the SmartPLS results tables, this kind computation was implemented into SmartPLS to get the t-value:
w / se
If you do not "like" this kind of "standard" computation for any reason, you can just take the bootstrap results for each subsample (just look into the results tables) and compute the t-value as you prefer
Prof. Dr. Christian M. Ringle, Hamburg University of Technology (TUHH), SmartPLS
- Literature on PLS-SEM: https://www.smartpls.com/documentation
- Google Scholar: https://scholar.google.de/citations?use ... AAAJ&hl=de
- Literature on PLS-SEM: https://www.smartpls.com/documentation
- Google Scholar: https://scholar.google.de/citations?use ... AAAJ&hl=de