Stop Criterion Changes
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- PLS Expert User
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Stop Criterion Changes
Hi,
Sorry, how can I understand if the stop criterion of the algorithm was reached and not the maximum number of iterations or not?
Sorry, how can I understand if the stop criterion of the algorithm was reached and not the maximum number of iterations or not?
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- SmartPLS Developer
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- Real name and title: Dr. Jan-Michael Becker
Re: Stop Criterion Changes
Well you see the number of Iterations in the report "Stop Criterion Changes" (number of rows). If the number of Iterations was smaller than the maximum number of iterations defined, the algorithem stopped because of the stop criterion.
Dr. Jan-Michael Becker, BI Norwegian Business School, SmartPLS Developer
Researchgate: https://www.researchgate.net/profile/Jan_Michael_Becker
GoogleScholar: http://scholar.google.de/citations?user ... AAAJ&hl=de
Researchgate: https://www.researchgate.net/profile/Jan_Michael_Becker
GoogleScholar: http://scholar.google.de/citations?user ... AAAJ&hl=de
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- PLS Expert User
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Re: Stop Criterion Changes
Thank you Dr. Jan-Michael Becker for your help
The stop criterion (10^-x): 7 is defined in smartpls algorithm, when I use my conceptual model with main effects; and after runing PLS algorithm, the number of rows (Stop Criterion Changes) will be 6. and when I use my conceptual model with main + moderating effects; the number of rows (Stop Criterion Changes) will be 3.
Is the number 6 (number of rows) sufficient?
How about the number 3 (number of rows) of moderating effects?
Thank again Dr. Jan-Michael Becker
The stop criterion (10^-x): 7 is defined in smartpls algorithm, when I use my conceptual model with main effects; and after runing PLS algorithm, the number of rows (Stop Criterion Changes) will be 6. and when I use my conceptual model with main + moderating effects; the number of rows (Stop Criterion Changes) will be 3.
Is the number 6 (number of rows) sufficient?
How about the number 3 (number of rows) of moderating effects?
Thank again Dr. Jan-Michael Becker
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- SmartPLS Developer
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Re: Stop Criterion Changes
It says that your model converges in 3 or 6 iterations. That is good (fast)! The longer it takes (the more iterations) the higher is the likelihood for problems in your model.
Dr. Jan-Michael Becker, BI Norwegian Business School, SmartPLS Developer
Researchgate: https://www.researchgate.net/profile/Jan_Michael_Becker
GoogleScholar: http://scholar.google.de/citations?user ... AAAJ&hl=de
Researchgate: https://www.researchgate.net/profile/Jan_Michael_Becker
GoogleScholar: http://scholar.google.de/citations?user ... AAAJ&hl=de
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- PLS Expert User
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Re: Stop Criterion Changes
You are so kind Doctor,
Thank you
Thank you
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Re: Stop Criterion Changes
Good morning,
In the paper (A new criterion for assessing discriminant validity in variance-based structural equation modeling) that you added a vedio on (https://www.youtube.com/watch?v=Uwo2cBtT_xo)
The authors ,in the table 6, utilized the following expretion: CI.900 [0.612;0.652]
I understand that CI means “Confidence Intervals”, but I do not understand what the two values [0.612;0.652] mean?
Where do I find them in smartPLS
Tank you Sir
In the paper (A new criterion for assessing discriminant validity in variance-based structural equation modeling) that you added a vedio on (https://www.youtube.com/watch?v=Uwo2cBtT_xo)
The authors ,in the table 6, utilized the following expretion: CI.900 [0.612;0.652]
I understand that CI means “Confidence Intervals”, but I do not understand what the two values [0.612;0.652] mean?
Where do I find them in smartPLS
Tank you Sir
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Re: Stop Criterion Changes
Good morning,
The authors, Henseler et al. (2015), P. 129, in the table 6, utilized the following expretion: CI.900 [0.612;0.652]
I understand that CI means “Confidence Intervals”, but I do not understand what the two values [0.612;0.652] mean?
Where do I find them in smartPLS
Tank you
The authors, Henseler et al. (2015), P. 129, in the table 6, utilized the following expretion: CI.900 [0.612;0.652]
I understand that CI means “Confidence Intervals”, but I do not understand what the two values [0.612;0.652] mean?
Where do I find them in smartPLS
Tank you
- cringle
- SmartPLS Developer
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Re: Stop Criterion Changes
It's the lower and the upper bound of the confidence interval.
Prof. Dr. Christian M. Ringle, Hamburg University of Technology (TUHH), SmartPLS
- Literature on PLS-SEM: https://www.smartpls.com/documentation
- Google Scholar: https://scholar.google.de/citations?use ... AAAJ&hl=de
- Literature on PLS-SEM: https://www.smartpls.com/documentation
- Google Scholar: https://scholar.google.de/citations?use ... AAAJ&hl=de
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- PLS Expert User
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Re: Stop Criterion Changes
Thank you Professor for your help
CI.900 [0.612;0.652]
Does CI.900 mean CI 90% ?
if it is yes.
Does the bootstrapping calculat CI automatically with 90% or what?
Thank you
CI.900 [0.612;0.652]
Does CI.900 mean CI 90% ?
if it is yes.
Does the bootstrapping calculat CI automatically with 90% or what?
Thank you
- cringle
- SmartPLS Developer
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- Joined: Tue Sep 20, 2005 9:13 am
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Re: Stop Criterion Changes
Sure 90% - and that's what SmartPLS computes. More info on confidence intervals: http://en.wikipedia.org/wiki/Confidence_interval
Prof. Dr. Christian M. Ringle, Hamburg University of Technology (TUHH), SmartPLS
- Literature on PLS-SEM: https://www.smartpls.com/documentation
- Google Scholar: https://scholar.google.de/citations?use ... AAAJ&hl=de
- Literature on PLS-SEM: https://www.smartpls.com/documentation
- Google Scholar: https://scholar.google.de/citations?use ... AAAJ&hl=de
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- PLS Expert User
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- Real name and title: Choukri MENIDJEL
Re: Stop Criterion Changes
Great Professor
Thank you
Thank you
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Re: Stop Criterion Changes
Hi,
To calculate Confidence Intervals, should I use bootstrapping with one-tailed or two tailed
Thank you
To calculate Confidence Intervals, should I use bootstrapping with one-tailed or two tailed
Thank you
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- PLS Expert User
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Re: Stop Criterion Changes
Hi everyone,
I have found that the researchers have used the following expretion in their articles, [based on t(4999), one-tailed test], why do they not use this one [based on t(5000), one-tailed test]
I look forward to hear your responds
Thank you
I have found that the researchers have used the following expretion in their articles, [based on t(4999), one-tailed test], why do they not use this one [based on t(5000), one-tailed test]
I look forward to hear your responds
Thank you