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Hi, is anybody aware of papers that deal with control variables in PLS PM? I am particularly interested in papers that deal explicitely with formative multi item constructs as control variables. Example: I have a set of formative dummy variables and want to assess their effect on a endogeneous const...

Hi,
is there an option to pull a new activation key before the current one is expired? I know that each key can be used on 3 computers simultaneously.
I somehow messed up with this and hence cannot start smartPLS on my laptop anymore. Or could you activate my key for 4 PC's?
Thanks, Andreas

Hi, although there is already an entry concerning the bootstrap error: "A singular matrix occured...." I have made an interesting observation which I want to share with the smartPLS developers. It seems that XLSTAT can run easily bootstrapping (dont worry, I use mainly smartPLS) even with ...

I would rather prefer confidence intervalls (bias corrected and accelerated) - the p-value assumes that your bootstrap distribution is normal (or t-type) and it is generated under Ho. In addition, the width of the CI provides you additional information.

Hi, just tried to apply the Efron and Tibshirani (1994) procedure (bias corrected and accelerated bootstrap confidence interval) to the raw data of the bootstrap output. Unfortunately this procedure can not be implemented as the jacknife type outputs for the acceleration factor are mssing. Might be ...

How did you run the ANOVA test? I might be able to help as I used also control variables in my study but you need to explain in more detail what you did (did you run the ANOVA with the latent variable scores?, how did you assess significance in PLS?)

Hi Markus, the way I did it was to copy the LV scores and the indicator data from smartPLS into any statistical package to perform scatter plots (or even better are matrix plots) and to run simple/multiple regressions. In most of the statistical packages you get then important info like observations...

Thanks, although this is not answering the question; refer to the comment which I have found under the link you quoted: "Theory tells us that the standard error of the sample mean equals the population standard deviation divided by the square root of the sample size. In cases in which the popul...

Hi chinasun - in case you have found the link could you pleaes quote it here? I didnt find the link unfortunately.

hmmm, how do explain then the numbers from my example, taken directly from the software report (not by blindfolding!).
E.g.
Rsqr(block j) * Communality (block j) = Redundancy (block j)
0.4044 * 0.5324 = 0.1975??

According to the paper of Tenenhaus et al. the redundancy for a generic endogeneous block j is computed as the product of the communality of block j with the Rsqr of block j. This does not match in my case. Example is below: R Square Communality Redundancy 0.4044 0.5324 0.1975 0 1 0 0.4495 1 0.231 0...